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Summary of Date objects in JavaScript

黄舟
Release: 2017-10-12 10:51:44
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In daily life, various forms of time characters are everywhere. The emergence of the concept of time, the invention of time units and timing tools have brought about changes to human beings that are difficult to describe in just one word. Today let’s talk about dates. Let’s take a look at the Date object in JavaScript.

Date object is one of the more commonly used objects, but many people do not know how to operate it at all. Even for some simple operations, they use moment without trying it themselves.

This time I will share the date usage skills in Date, hoping to inspire everyone.

MDN official website introduction

The setDate() method specifies the number of days in a date object based on local time.

If dayValue is outside the reasonable range of the month, setDate will update the Date object accordingly.

For example, if you specify 0 for dayValue, the date will be set to the last day of the previous month.

Get the number of days in the month


// 获取月份天数
function getMonthDayCount(year, month) {
 return new Date(year, month, 0).getDate();
}
console.log(getMonthDayCount(2017, 10)); // 31
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Date The essence of the third parameter is the same as setDate.

Because when date is 0, it automatically returns to the last day of the previous month, so there is no need to decrease the month here, which is just right.

Get the number of days in all months


function getAllMonthDayCount(year) {
 var days = [31, new Date(year, 2, 0).getDate(), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];
 return days;
}
console.log(getAllMonthDayCount(2016));// [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
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This is an extension of the above, not much explanation.

Is it a leap year?


function isLeapYear(year) {
 return (year % 4 == 0) && (year % 100 != 0 || year % 400 == 0);
}
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This is the code on the Internet, I believe most people use it.

But do you really understand or remember it?

I can’t anyway. .


function isLeapYear(year) {
 return new Date(year, 2, 0).getDate() === 29;
}
console.log([
 isLeapYear(2000),
 isLeapYear(2016),
 isLeapYear(2017),
 isLeapYear(2018)
]); // [ true, true, false, false ]
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Looking at it this way, it is very simple and easy to understand.

And you don’t need to remember it. Do you think you can’t forget it even if you want to?

Addition and subtraction of days

I have seen someone use relative seconds to calculate days before or after days, or even across months and years. Condition.

In fact, just setDate directly, and it will automatically handle the situation of crossing months and years.


// 10天后是几月几号
var dt = new Date('2016-12-25');
dt.setDate(dt.getDate() + 10);
console.log(dt.toLocaleDateString()); // 2017/1/4


// 10天前是几月几号
var dt = new Date('2017-01-04');
dt.setDate(dt.getDate() - 10);
console.log(dt.toLocaleDateString()); // 2016/12/25
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Summary

Although these things are very basic, everyone may know the name of the method, but many people still don’t Will use it.

It’s the same as using jq but still using a for loop to process the results.

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