PHP implements an example of encapsulating a single file and uploading it to the database-PHP Tutorial-php.cn

PHP implements an example of encapsulating a single file and uploading it to the database

黄舟

Release： 2023-03-16 16:30:01

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This article mainly introduces the relevant information of PHP encapsulating a single file to be uploaded to the database (path). Friends in need can refer to it

1. First think about the question of uploading to the database whether it is an uploaded picture or a picture Address: What we upload here is the image address. Because the image or audio is too large to be stored in the database, the database will collapse.

The following is the method for uploading encapsulated files:

<?php
/*
*@prame string key
*@prame string path
*@prame String maxSize
*@prame array allowMime
*@prame array allowFiletype
*@prame bool true
*
*auther wulei
*/
function upload($key,$path,$maxSize,$allowMime,$allowType,$ifFileName = true){
  //第一步 判断错误码
  if($_FILES[$key][&#39;error&#39;]){
    switch($_FILES[$key][&#39;error&#39;]){
      case 1:
        $str = "上传的文件超过了 php.ini 中 upload_max_filesize 选项限制的值。";
        break;
      case 2:
        $str = "上传文件的大小超过了 HTML 表单中 MAX_FILE_SIZE 选项指定的值。";
        break;
      case 3:
        $str = "文件只有部分被上传。";
        break;
      case 4:
        $str = "没有文件被上传。";
        break;
      case 6:
        $str = "找不到临时文件夹。";
        break;
      case 7:
        $str = "文件写入失败";
        break;
    }
    return [0,$str];
  }
  //判断文件大小
  if($_FILES[$key][&#39;size&#39;]>$maxSize){
    return [0,&#39;传的文件超过最大限制&#39;];
  }
  //判断文件的mime类型
  if(!in_array($_FILES[$key][&#39;type&#39;],$allowMime)){
    return [0,&#39;不符合的mime类型&#39;];
  }
  //判断文件的后缀
  $info = pathinfo($_FILES[$key][&#39;name&#39;]);
  $sub = $info[&#39;extension&#39;];
  if(!in_array($sub,$allowType)){
    return [0,&#39;不符合的文件后缀&#39;];
  }
  //判断是否是随机文件
  if($ifFileName){
    $name = uniqid().&#39;.&#39;.$sub;
  }else{
    $name = $info;
  }
  //拼接路径
  $path = rtrim($path,&#39;/&#39;).&#39;/&#39;.date(&#39;Y/m/d&#39;).&#39;/&#39;;
  //判断文件是否存在,不存在则创建
  if(!file_exists($path)){
    mkdir($path,0777,true);
  }
  //判断是否是上传文件
  if(is_uploaded_file($_FILES[$key][&#39;tmp_name&#39;])){
    if(move_uploaded_file($_FILES[$key][&#39;tmp_name&#39;],$path.$name)){
      echo &#39;文件上传成功&#39;;
      return [1,$path.$name];
    }else{
      return[0,&#39;上传文件失败&#39;];
    }
  }else{
    return [0,&#39;文件不存在&#39;];
  }
  }

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2.html page

<html>
<head>
  <title>文件上传</title>
  <meta charset = "utf-8"/>
</head>
<body>
  <form action = "onUpload.php" method = "post" enctype ="multipart/form-data">
    <!--<input type = "text" name = "username"/><br/>-->
    <input type = "file" name = "file"/><br/>
    <input type = "submit" value ="提交"/>
  </form>
</body>

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3. Next we link to the database

Here we use it directly. If you don’t understand, you can read the previous article on the encapsulated database method. Article

<?php
  //包含方法
  include &#39;uploed.php&#39;;
  include &#39;common.php&#39;;
  //得到方法
  $data = upload(&#39;file&#39;,&#39;image&#39;,pow(1024,2)*2,[
        &#39;image/png&#39;,&#39;image/jpeg&#39;,&#39;image/gif&#39;,&#39;image/wbmp&#39;
      ],[&#39;png&#39;,&#39;jpg&#39;,&#39;jpeg&#39;,&#39;jpe&#39;,&#39;pjpeg&#39;,&#39;gif&#39;,&#39;wbmp&#39;,&#39;bmp&#39;]);
  //这里进行数据库操作
  if($data[0]){
    $date[&#39;img_path&#39;] = $data[1];
  }
  insert($link,&#39;user&#39;,$date);

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Summary

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