Regular example sharing for matching url parameters

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Release: 2023-03-20 19:20:02
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本文主要和大家分享匹配url参数的正则实例,希望能帮助到大家。

/([^?&=]+)=([^?&=]*)/g

解释:

前后的斜杠/是正则表达式的分隔符,最后的g表示全局匹配,匹配到第一个之后不会停下来,会继续匹配,相当于PHP里的preg_match_all,没有g就相当于preg_match,下面有例子说明.

()表示子组.

[^]表示字符类取反,比如[^abc]匹配的就是不是a和b和c的单个字符,[^?&=]匹配不是^和?和=的单个字符.

字符类[]后面的+和*表示量词:
+ 等价于 {1,} 重复1次或多次
* 等价于 {0,} 重复0次或多次

var str = "foo=bar&lang=js";var reg = /[^?&=]{1,}=[^?&=]{0,}/g;
console.log(str.match(reg)); //输出 ["foo=bar", "lang=js"]var str = "foo=bar&lang=js";var reg = /[^?&=]{1,}=[^?&=]{0,}/;
console.log(str.match(reg)); //输出 ["foo=bar"]var str = "foo=bar&lang=js";var reg = /([^?&=]{1,})=([^?&=]{0,})/;
console.log(str.match(reg)); //输出 ["foo=bar", "foo", "bar"]//下面是提取参数部分为转为对象的代码
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var getQueryObject=function (url) {
    url=url==null?window.location.href:url    var search=url.substring(url.lastIndexOf("?")+1)    var obj={}    //   ^?&= 匹配不是?或&或=的单个字符    var reg=/([^?&=]+)=([^?&=]*)/g    search.replace(reg,function (rs,$1,$2) {        debugger        var name=decodeURIComponent(arguments[1])        var val=decodeURIComponent(arguments[2])        obj[name]=val        return    })    return obj}
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