Before I wrote "A simple example of php returning json data", "php returns json data Chinese display problem" and "Using JSON in PHP language and restoring json to an array". Hope it helps everyone.
Example 1
test.html
<!doctype html> <html> <head> <meta charset="utf-8"> <title>test</title> <script src="jquery-1.5.2.min.js"></script> <script src="ajax.js"></script> </head> <body> </body> </html>
ajax.js
$.ajax({ type : "post", url : "ajax.php", dataType : "jsonp", jsonp: "callback",//传递给请求处理程序或页面的,用以获得jsonp回调函数名的参数名(默认为:callback) jsonpCallback:"success_jsonpCallback",//自定义的jsonp回调函数名称,默认为jQuery自动生成的随机函数名 success : function(json){ alert('success'); }, error:function(){ alert('fail'); } });
ajax.php
<?php $data = "......."; $callback = $_GET['callback']; echo $callback.'('.json_encode($data).')'; exit; ?>
jquery-1.5 .2.min.js
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When using jsonp, when calling a function in JSONP form, such as "myurl?callback=?" jQuery will automatically replace ? with The correct function name to execute the callback function.
Example 2
test.html
<!doctype html> <html> <head> <meta charset="utf-8"> <title>test</title> <script src="jquery-1.5.2.min.js"></script> <script src="ajax.js"></script> </head> <body> <form name="form"> <input type="text" name="sex"> <input type="text" name="age"> <input type="button" id="btn" value="button" /> </form> </body> </html>
ajax.js
$(document).ready(function(){ $("#btn").click(function(k) { //... var j = $("form").serializeArray();//序列化name/value $.ajax({ type: 'GET', //这里用GET url: 'ajax.php', dataType: 'jsonp', //类型 data: j, jsonp: 'callback', //jsonp回调参数,必需 async: false, success: function(result) {//返回的json数据 alert(result.message); //回调输出 result = result || {}; if (result.msg=='err'){ alert(result.info); }else if (result.msg=="ok"){ alert('提交成功'); }else{ alert('提交失败'); } }, timeout: 3000 }) //... }); });
ajax.php
<?php $callback = isset($_GET['callback']) ? trim($_GET['callback']) : ''; //jsonp回调参数,必需 $date = array("age"=>$_GET['age'], "message"=>$_GET['age']); $date["msg"]="err"; $date["info"]="因人品问题,发送失败"; $tmp= json_encode($date); //json 数据 echo $callback . '(' . $tmp .')'; //返回格式,必需 ?>
jquery-1.5.2. min.js
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