How to implement the function of prompting for input information in ajax-JS Tutorial-php.cn

How to implement the function of prompting for input information in ajax

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Release： 2018-03-30 17:31:06

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This time I will show you how ajax can realize the function of prompting for information input. What are the precautions for ajax to implement the function of prompting input information. The following is a practical case, let's take a look.

The example in this article shares the specific code for ajax to achieve the input prompt effect for your reference. The specific content is as follows

Website homepage

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8">
  <title>Title</title>
  <style>
    *{
      margin:0px auto;
      padding:0px;
    }
    .l{
      height:50px;
      width:198px;
      border-bottom:1px solid black;
      text-align: center;
      line-height:40px;
      vertical-align: middle;
    }
  </style>
  <script src="../wenjian/jquery-2.2.3.min.js"></script>
</head>
<body>
<p style="height: 50px;width: 200px"><input type="text" id="name" style="width: 198px;height: 48px;"></p>
<p id="list" style="height: 500px;width: 200px;border: 1px solid black">
<!--<p id="l">zhongguo</p>-->
</p>
</body>
</html>
<script>
$("#name").keyup(function () {
  var n = $("#name").val();
  if (n != ""){
  $.ajax({
    url:'ltchuli.php',
    data:{n:n},
    type:'post',
//    dataType:'text',
    dataType:'json',
    success:function (data) {
//text写法
//     var s = data.split("|");
//     var str = "";
//     for (var i=0;i<s.length;i++)
//     {
//       str = str + "<p class=&#39;l&#39;>" +s[i] +"</p>";
//     }
//     $("#list").html(str);
//json写法
      for (var i in data){
        $("#list").append("<p class=&#39;l&#39;>" +data[i] +"</p>");
      }
    }
  });
}else {
    $("#list").html("");
  }
})
</script>

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Processing page

<?php
/**
 * Created by fcc
 * User: Administrator
 * Date: 2017/10/30
 * Time: 9:52
 */
$n = $_POST[&#39;n&#39;];
require_once "../wenjian/DBDA.class.php";
$db = new DBDA();
$obj = "select region_name from region WHERE region_name LIKE &#39;%{$n}%&#39; ";
$data = $db->Query($obj);
//echo $data;
echo json_encode($data);

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I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!