Ajax implements paging query function
This time I will bring you the ajax implementation of the paging query function. What are the precautions for the ajax implementation of the paging query function? The following is a practical case, let's take a look.
The specific code of ajax paging query function is for your reference. The specific content is as followsThe displayed effect is as follows:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>无标题文档</title>
<link type="text/css" rel="stylesheet" href="../bootstrap-3.3.7-dist/css/bootstrap.min.css" rel="external nofollow" />
<script src="../jquery-3.2.0.min.js"></script>
<script src="../bootstrap-3.3.7-dist/js/bootstrap.min.js"></script>
<style type="text/css">
.list:hover{ cursor:pointer}
#prev:hover{ cursor:pointer}
#next:hover{ cursor:pointer}
</style>
</head>
<body>
<p class="page-header">
<h1>AJAX分页</h1>
</p>
<p>名称：<input type="text" id="name" /> <button type="button" class="btn btn-info btn-xs" id="chaxun">查询</button></p>
<br />
<table width="100%" class="table table-hover">
<tr>
<td>代号</td>
<td>名称</td>
</tr>
<tbody id="shuju">
</tbody>
</table>
<br />
<ul class="pagination" id="xinxi"></ul>
</body>
<script type="text/javascript">
//代表当前页
var page = 1;
//每页显示几条
var num = 5;
//加载数据
Load();
//加载分页列表
LoadFenYe();
//加载数据的方法
function Load()
{
var name = $("#name").val();
$.ajax({
url:"chuli.php",
data:{page:page,num:num,name:name},
type:"POST",
dataType:"JSON",
success: function(data){
var str = "";
for(var k in data)
{
str = str + "<tr><td>"+data[k].code+"</td><td>"+data[k].nno+"</td></tr>";
}
$("#shuju").html(str);
}
});
}
//加载分页信息
function LoadFenYe()
{
//存储所有分页信息的代码
var s = "";
var name = $("#name").val();
//加载上一页
s = "<li><a id='prev'>«</a></li>";
//加载列表
var zts = 0;
$.ajax({
async:false,
data:{name:name},
type:"POST",
url:"zongtiaoshu.php",
dataType:"TEXT",
success: function(data){
zts = data;
}
});
//求总页数
var zys = Math.ceil(zts/num);
//为了防止出错
page = parseInt(page);
for( var i=page-2;i<page+3;i++)
{
if(i>0 && i<=zys)
{
if(i==page)
{
s = s+"<li class='active'><a ys='"+i+"' class='dangqian'>"+i+"</a></li>";
}
else
{
s = s+"<li><a ys='"+i+"' class='list'>"+i+"</a></li>";
}
}
}
//加载下一页
s = s+"<li><a id='next'>»</a></li>";
$("#xinxi").html(s);
//给上一页加事件
$("#prev").click(function(){
page = parseInt(page);
if(page>1)
{page--;}
//重新加载数据
Load();
//重新加载分页信息
LoadFenYe();
})
//给下一页加事件
$("#next").click(function(){
page = parseInt(page);
if(page<zys)
{page++;}
//重新加载数据
Load();
//重新加载分页信息
LoadFenYe();
})
//给列表加事件
$(".list").click(function(){
page = parseInt($(this).attr("ys"));
//重新加载数据
Load();
//重新加载分页信息
LoadFenYe();
})
}
$("#chaxun").click(function(){
//重新加载数据
Load();
//重新加载分页信息
LoadFenYe();
})
</script>
</html><?php
$page = $_POST["page"];
$num = $_POST["num"];
$name = $_POST["name"];
require "../DBDA.class.php";
$db = new DBDA();
$tguo = ($page-1)*$num;
$sql = "select * from nation where nno like '%{$name}%' limit {$tguo},{$num}";
echo $db->jsonquery($sql);
<?php
$name = $_POST["name"];
require"../DBDA.class.php";
$db = new DBDA();
$sql ="select count(*) from nation where nno like '%{$name}%'";
echo $db->strquery($sql);How to use ajax to submit comments and automatically refresh
How to let the browser remember the ajax request And control the browser forward and backward
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