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php中判断一个字符串包含另一个字符串的方法_php技巧

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Release： 2016-05-17 09:40:17
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$name = "001x.gif";
$pan = "x";
$con = explode($pan,$name);
if (count($con)>1):
echo $name."中包含".$pan;
else:
echo $name."中没有包含".$pan;
endif;
?> 

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php中判断一个字符串包含另一个字符串的方法
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