php bootstrap ajax form submission

PHPz
Release: 2023-03-23 18:46:02
Original
2749 people have browsed it

This article introduces the php bootstrap ajax form submission. Now I share it with everyone. Friends in need can refer to it

Post the code directly:

<!DOCTYPE html>
<html lang="zh-CN">
<head>
    <meta charset="utf-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <!-- 上述3个meta标签*必须*放在最前面,任何其他内容都*必须*跟随其后! -->
    <title>Bootstrap 101 Template</title>

    <!-- Bootstrap -->
    <!--<link href="css/bootstrap.min.css" rel="stylesheet">-->
    {load href="__STATIC__/bootstrap/css/bootstrap.min.css"}
    {load href="__STATIC__/css/base.css"}

    <!-- HTML5 shim and Respond.js for IE8 support of HTML5 elements and media queries -->
    <!-- WARNING: Respond.js doesn&#39;t work if you view the page via file:// -->
    <!--[if lt IE 9]>
    <script src="https://cdn.bootcss.com/html5shiv/3.7.3/html5shiv.min.js"></script>
    <script src="https://cdn.bootcss.com/respond.js/1.4.2/respond.min.js"></script>
    <![endif]-->
</head>
<body>
<p class="container" style="background: #fff;min-height: 200px;">
    <!--一行内容-->
    <p class="row">
        <p class="col-md-3"></p>
        <p class="col-md-6" style="background: #fff;min-height: 150px;">
            <p class="login-header">用户登录</p>
            <p class="login-form">
                <p class="alert alert-danger error-tips" style="display: none;" role="alert"></p>
                <p class="alert alert-success success-tips" style="display: none;" role="alert"></p>

                <form class="login">
                    <p class="form-group">
                        <label for="exampleInputEmail1">用户名</label>
                        <input type="text" name="name" class="form-control" id="exampleInputEmail1"
                               placeholder="请输入您的邮箱">
                    </p>
                    <p class="form-group">
                        <label for="exampleInputPassword1">密码</label>
                        <input type="password" name="password" class="form-control" id="exampleInputPassword1"
                               placeholder="请输入您的密码">
                    </p>
                    <p class="checkbox">
                        <label>
                            <input type="checkbox"> 下次自动登录
                        </label>
                    </p>
                    <button type="button" class="btn btn-default login-btn">用户登录</button>
                </form>
            </p>
        </p>
        <p class="col-md-3"></p>
        <!--<p class="col-md-8" style="background: #999;min-height: 150px;">右侧菜单</p>-->
    </p>
</p>
<!--<p class="container-fuild" style="background: #eee;min-height: 200px;">-->
<!--<h1>你好,世界!</h1>-->
<!--</p>-->

<!-- jQuery (necessary for Bootstrap&#39;s JavaScript plugins) -->
<!--<script src="https://cdn.bootcss.com/jquery/1.12.4/jquery.min.js"></script>-->
{load href="__STATIC__/jquery/jquery.min.js"}
<!-- Include all compiled plugins (below), or include inpidual files as needed -->
{load href="__STATIC__/bootstrap/js/bootstrap.min.js"}
<!--<script src="js/bootstrap.min.js"></script>-->
<script>
    $(function(){
        // 给登录按钮增加事件监听
        $(&#39;.login-btn&#39;).click(function(){

            //alert(&#39;你点击了登录按钮&#39;);
            // 1 获取表单的数据【一般会在javascript中进行验证】
            // 2 使用ajax方法进行提交
            // 3 根据服务器的返回值进行操作(具体局部刷新操作)

            // 1.挨个获取
            var _name = $(&#39;input[name="name"]&#39;).val();
            var _password = $(&#39;input[name="password"]&#39;).val();

            // 2.使用jq的serialize()
            // alert($(&#39;.login&#39;).serialize());
            //alert(_password);

            //todo::前端js数据验证

            $.ajax({
                type : &#39;POST&#39; ,
                url : "{:url(&#39;checkLoginData&#39;)}",
                data : $(&#39;.login&#39;).serialize(),
                dataType: &#39;json&#39;,
                success : function(data)
                {
//                    console.log(data);
                    if(data.status == 0)
                    {
                        $(&#39;.error-tips&#39;).text(data.msg).show();
                    }
                    else
                    {
                        $(&#39;.success-tips&#39;).text(data.msg).show();
                        setTimeout(function(){
                            window.location.href = "{:url(&#39;index&#39;)}";
                        },2000);
                    }
                }
            })

        })
    })
</script>
</body>
</html>
Copy after login

Related recommendations:

Bootstrap tutorial

Detailed explanation of various classic algorithms implemented in PHP

The above is the detailed content of php bootstrap ajax form submission. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!