How to read txt data file into matrix in Python3
Below I will share with you a method of reading txt data files into a matrix in Python3. It has a good reference value and I hope it will be helpful to everyone. Let’s take a look together
1. Example program:
''' 数据文件:2.txt内容:(以空格分开每个数据) 1 2 2.5 3 4 4 7 8 7 ''' from numpy import * A = zeros((3,3),dtype=float) #先创建一个 3x3的全零方阵A,并且数据的类型设置为float浮点型 f = open('2.txt') #打开数据文件文件 lines = f.readlines() #把全部数据文件读到一个列表lines中 A_row = 0 #表示矩阵的行,从0行开始 for line in lines: #把lines中的数据逐行读取出来 list = line.strip('\n').split(' ') #处理逐行数据:strip表示把头尾的'\n'去掉,split表示以空格来分割行数据,然后把处理后的行数据返回到list列表中 A[A_row:] = list[0:3] #把处理后的数据放到方阵A中。list[0:3]表示列表的0,1,2列数据放到矩阵A中的A_row行 A_row+=1 #然后方阵A的下一行接着读 #print(line) print(A) #打印 方阵A里的数据 打印结果: [[ 1. 2. 2.5] [ 3. 4. 4. ] [ 7. 8. 7. ]]
2. The logic of reading data into the matrix:
is a simple explanation. For example, we need to:
1 2 3
4 5 6
7 8 9
Read into the matrix, take the above code as an example:
When When A_row =0, after executing A[A_row:] = list[0:3], the matrix A is:
2 | 3 | |
2 | 3 | |
2 | 3 |
When A_row = 1, execute A[A_row:] = list[0:3] after matrix A Is:
2 | 3 | |
5 | 6 | |
5 | 6 |
2 | 3 | |
5 | 6 | |
8 | 9 |
What
for line in lines: #先把逐行数据取出来 list = line.strip('\n').split(' ') #再通过处理,放回到list列表中 A[A_row:] = list[0:3] #然后把list列表的数据放到矩阵中 A_row+=1
How to read TXT files in Python
How to generate a list by reading file names in python
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