How to implement operator overloading in JS
This time I will show you how to implement operator overloading in JS, and what are the notes for implementing operator overloading in JS. The following is a practical case, let’s take a look.
I have been doing data processing recently, and I have customized some data structures, such as Mat, Vector, Point, etc. I have to repeatedly define the four arithmetic operations such as addition, subtraction, multiplication and division. The code is not very intuitive, javascript The lack of operator overloading in C and C# is really frustrating, so I wanted to "save the country" by automatically implementing operator overloading in the translation code. The implementation idea is actually very simple, which is to write an interpreter and compile the code. For example:
S = A B (B - C.fun())/2 D
is translated into
`S = replace(replace(A, ' ', replace( replace(B,'',(replace(B,'-',C.fun())))),'/',2),' ',D)`
In the replace function we Call the corresponding operator function of the object. The replace function code is as follows:
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The implementation of replacement is very simple. Without too much explanation, the important part is how to compile the code. The implementation of the four arithmetic operations when studying data structure in college is the basis of this translation, with slight differences. Briefly describe the process:
1. Split the expression, extract variables and operators to obtain the metaarray A
2. Traverse the metaarray
If the elements are operators addition, subtraction, multiplication and division, then from Pop the previous element from the stack and convert it to replace(last, operator,
If the element is ')', pop the element from the stack, splice it until it encounters '(', and push it into the stack. You need to pay attention here' ('Whether there is a function call or replace before the element. If it is a function call or replace, you need to continue to pop the data forward and close the replacement function.
If it is a general element, check whether the previous element is replaced. If so , you need to splice ')' to close the replace function, otherwise push the elements directly onto the stack
3. Combine the stack sequence obtained in step 2 to get the compiled expression
##. #According to the above process, implement the code:1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 |
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Use operator overloading. For those that inherit from non-OOkay classes, we can use injection, as follows:
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Another option is to pass the code as a parameter into the $$ method, which compiles the code and executes it, as follows:
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