python3 gets the upper-level directory instance of the current file

This article mainly introduces the example of python3 getting the upper-level directory of the current file. It has certain reference value. Now I share it with you. Friends in need can refer to it

Because using python selenium has Sometimes I need to get the upper-level directory of the current file. I found it after searching for a while and recorded it here;

os.path.dirname(os.path.dirname(os.path .abspath(__file__))) This is to get the upper-level directory of the current file

##sys.path.append(os.path.dirname(os.path .dirname(os.path.abspath(__file__)))) This is to add the path to the system environment variable

os.path.abspath(os. path.join(os.path.dirname(__file__),"..")) #Get the root path of the current project

My own example:

A and B folders are at the same level. There is a.py under folder A. Now I want to reference a.py of folder A in folder B. At this time I can add sys.path.append(os.path.dirname(os.path.dirname(os.path.abspath(__file__)))) to B’s file. In this case, I can directly import a and reference a

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