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Detailed explanation of the steps to pass json parameters in the $http method

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Release: 2018-05-08 11:09:55
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This time I will give you a detailed explanation of the steps for passing json parameters through the $http method. What are the precautions for passing json parameters through the $http method? The following is a practical case, let's take a look.

The details are as follows:

1. The default data type submitted by the $http POST method is application/json

var data = {'wid':'0', 'praise' : '25'}; 
$http.post(url, data).success(function(result) { 
 // 
});
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The final request sent is:

POST http://www.example.com HTTP/1.1 
Content-Type: application/json;charset=utf-8 
 
{'wid':'0','praise':'25'}
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The default method can directly pass the json object to the server in the form of

string, which is more suitable for RESTful interfaces. But the $_POST of the php script cannot get the json data from the request body.

You can use this:

$data = file_get_contents("php://input"); //获得原始输入流
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Note: php://input is invalid when enctype="multipart/form-data"

After obtaining the original input stream of the request and then processing it accordingly, you can get the json data.

2. Submit the json data using x-www-form-urlencoded method

app.factory("Comment",function($http){
 return {
  get : function(commentFileUrl) {
   return $http({
    method: "GET",
    url: commentFileUrl,
    params: {R:Math.random()},
    headers: {'Cache-Control':'no-cache'}
   });
  },
  //保存一个评论
  save : function(toUrl,saveFileUrl,Data) {
   $http({
    method: "POST",
    url: toUrl,
    data: {saveUrl:saveFileUrl,commit:Data},
    headers: { 'Content-Type': 'application/x-www-form-urlencoded' },
    transformRequest: function(obj) {
     var str = [];
     for (var p in obj) {
      str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
     }
     return str.join("&");
    }
   }).success(function(data){
    console.log("数据已保存!");
   }).error(function(data) {
    alert("数据保存失败,错误信息:" + JSON.stringify({data:data}));
   });
  }
 }
});
var updateClickRate={'wid':'0','click_rate':'87'};
Comment.save("php/updateWork.php","../userdata/work_content.json",JSON.stringify(updateClickRate));
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Finally sent request It is:

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!

Recommended reading:

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The above is the detailed content of Detailed explanation of the steps to pass json parameters in the $http method. For more information, please follow other related articles on the PHP Chinese website!

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