This time I will bring you JS to implement the array deduplication algorithm. What are the precautions for JS to implement the array deduplication algorithm? . Here is a practical case, let’s take a look.
Test case:
arr = ["1",3,"1",1,4,5,1,"2",5,1,{"name ":"li","age":20},2,4,3,{"name":"li","age":20},""];
Method 1: With the help of temporary array and indexOf, The algorithm complexity is: O(n^2)
function unique1(arr){ var temp = []; for(var i=0; i<arr.length; i++){ if(temp.indexOf(arr[i]) == -1){ temp.push(arr[i]); } } return temp; }
Test result:
unique1(arr): ["1", 3, 1, 4, 5, "2", Object { name="li", age=20}, 2, Object { name="li", age=20}, ""]
bug Unable to distinguish objects
Method 2: Use Object object in JavaScript as Ha Greek table
function unique2(arr){ var temp=[]; var hash={}; for(var i=0; i<arr.length;i++){ if(!hash[arr[i]]){ hash[arr[i]]=true; temp.push(arr[i]); } } return temp; }
Test result:
unique2(arr): ["1", 3, 4, 5, "2", Object { name="li ", age=20}, ""]
bug: Unable to distinguish: 1 and "1"
Modification
function unique2(arr){ var temp=[]; var hash={}; for(var i=0; i<arr.length;i++){ var item = arr[i]; var key = typeof(item)+item; if(!hash[key]){ hash[key]=true; temp.push(arr[i]); } } return temp; }
Test result:
unique2(arr): ["1", 3, 1, 4, 5, "2", Object { name="li", age=20}, 2, ""]
Method 3: First use sort to sort the array, and then use a temporary array to store the last one of the same element. This method can only be used for pure Number type arrays
function unique3(arr){ arr.sort(function(a,b){ return a-b; }); var temp = []; for(var i=0;i<arr.length;i++){ if(arr[i] !== arr[i+1]){ temp.push(arr[i]); } } return temp; }
I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!
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