AJAX is used to determine whether the user is registered
This article mainly introduces AJAX in detail to determine whether the user is registered, which has certain reference value. Interested friends can refer to it
On many registration pages, we may We will encounter the following situations. When we register a user name, we may be prompted that the user name has been registered. The implementation is to apply AJAX technology.
First write a login page
<html>
<head>
<title></title>
<script type="text/javascript">
var xmlHttp;
var flag;
function createXMLHttp(){
if(window.XMLHttpRequest){
xmlHttp=new XMLHttpRequest();
}else{
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
}
}
function checkUserid(userid){
createXMLHttp();
xmlHttp.open("POST","CheckServlet?userid="+userid);
xmlHttp.onreadystatechange=checkUseridCallback;
xmlHttp.send();
document.getElementById("msg").innerHTML="正在验证。。。";
}
function checkUseridCallback(){
if(xmlHttp.readyState==400){
if(xmlHttp.status==200){
var text=xmlHttp.responseText;
if(text=="true"){
flag=false;
document.getElementById("msg").innerHTML="用户ID重复，无法使用";
}else{
flag=true;
document.getElementById("msg").innerHTML="此用户ID可以注册";
}
}
}
}
function checkForm(){
return flag;
}
</script>
</head>
<body>
<form action="tt.jsp" method="post" onsubmit="return checkForm()">
用户ID <input type="text" name="userid" onblur="checkUserid(this.value)"><span id="msg"></span><br>
姓名：<input type="text" name="name"><br>
密码：<input type="password" name="password"><br>
<input type="button" value="注册">
<input type="reset" value="重置">
</form>
</body>
</html>Then write a servlet Java code
import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class CheckServlet extends HttpServlet{
public static final String DBDRIVER = "oracle.jdbc.OracleDriver";
public static final String DBURL = "jdbc:oracle:thin:@59.173.240.149:1521:heer";
public static final String DBUSER = "hnsyu_dev";
public static final String DBPASS = "hnsyuok";
public void doGet(HttpServletRequest request,HttpServletResponse response)
throws ServletException,IOException{
this.doPost(request, response);
}
public void doPost(HttpServletRequest request,HttpServletResponse response)
throws ServletException,IOException{
request.setCharacterEncoding("gbk");
response.setContentType("text/html");
Connection connection = null;
PreparedStatement preparedStatement = null;
ResultSet resultSet = null;
PrintWriter out = response.getWriter();
String userid = request.getParameter("userid");
try {
Class.forName(DBDRIVER);
connection = DriverManager.getConnection(DBURL, DBUSER, DBPASS);
String sql = "select count(userid) from userdemo where userid=?";
preparedStatement = connection.prepareStatement(sql);
preparedStatement.setString(1,userid);
resultSet = preparedStatement.executeQuery();
if (resultSet.next()) {
if(resultSet.getInt(1)>0){
out.print("false");
System.out.println("true");
}else {
out.print("false");
}
}
out.close();
} catch (Exception e) {
e.printStackTrace();
}finally{
try {
connection.close();
} catch (Exception e) {
e.printStackTrace();
}
}
}
}You also need to configure it in web.xml
<?xml version="1.0" encoding="UTF-8"?> <web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"> <display-name></display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>CheckServlet</servlet-name> <servlet-class>CheckServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>CheckServlet</servlet-name> <url-pattern>/CheckServlet</url-pattern> </servlet-mapping> </web-app>
The above I compiled it for everyone. I hope it will be helpful to everyone in the future.
Related articles:
Perfect solution to ajax cross-domain requests Parsererror error
ajax submits the mobile phone number to the database for verification and returns the status value
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