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js method to obtain the current domain name, Url, relative path and parameters, and specified parameters

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Release: 2018-07-09 17:06:05
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This article mainly introduces the method of js to obtain the current domain name, Url, relative path and parameters, and specified parameters. It has a certain reference value. Now I share it with you. Friends in need can refer to it

1. Two ways to get the current domain name with js
Method one

 var domain = document.domain;
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Method two

var domain = window.location.host;
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Note: Since the current domain name obtained does not include http: //, so when assigning the obtained domain name to the href of the a tag, don't forget to add http://, otherwise navigation errors will occur when clicking the link.

2. 4 ways to get the current Url

var url = window.location.href;
  var url = self.location.href;
  var url = document.URL;
  var url = document.location;
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Note: What is displayed in the address bar is the URL obtained.

3. Method of obtaining the current relative path
First obtain the Url, then cut the Url into two parts through //, and then intercept the relative path from the latter part. If there are parameters in the intercepted relative path, remove the parameters.

function GetUrlRelativePath()
  {
    var url = document.location.toString();
    var arrUrl = url.split("//");
    var start = arrUrl[1].indexOf("/");
    var relUrl = arrUrl[1].substring(start);//stop省略,截取从start开始到结尾的所有字符
    if(relUrl.indexOf("?") != -1){
      relUrl = relUrl.split("?")[0];
    }
    return relUrl;
  }
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Calling method: GetUrlRelativePath();
Example: If the current Url is http//www.liangshunet.com/pub/item.aspx?t=osw7, then the intercepted relative path The path is: /pub/item.aspx.

4. How to get the current Url parameters
1. Get the Url parameter part

function GetUrlPara()
  {
    var url = document.location.toString();
    var arrUrl = url.split("?");
    var para = arrUrl[1];
    return para;
  }
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Calling method: GetUrlPara()
Example: If the current Url is http/ / www.liangshunet.com/pub/item.aspx?t=osw7, then the intercepted parameter part is: t=osw7.

5. Method of getting specified Url parameters

//paraName 等找参数的名称
  function GetUrlParam(paraName) {
    var url = document.location.toString();
    var arrObj = url.split("?");
    if (arrObj.length > 1) {
      var arrPara = arrObj[1].split("&");
      var arr;
      for (var i = 0; i < arrPara.length; i++) {
        arr = arrPara[i].split("=");
        if (arr != null && arr[0] == paraName) {
          return arr[1];
        }
      }
      return "";
    }
    else {
      return "";
    }
  }
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Calling method: GetUrlParam("id");
Example: If the URL of the web page has such a parameter test.htm?id =896&s=q&p=5, then call GetUrlParam("p") and return 5.

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