Java implementation code for adding two integers

The content of this article is about the implementation code of adding two integers in Java. It has certain reference value. Friends in need can refer to it. I hope it will be helpful to you.

The problem description is as follows:

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A B.

The reference code is as follows:

public static void main(String[] args) {
		// TODO Auto-generated method stub
		int s;
		String string1 = null;
		String string2 = null;
		Scanner scanner = new Scanner(System.in);
		string1 = scanner.nextLine();
		System.out.println("the first number:" + string1);
		string2 = scanner.nextLine();
		System.out.println("the second number:" + string2);

		char a1[] = string1.toCharArray();
		int a[] = new int[a1.length];
		for (int i = 0; i < a1.length; i++) {
			a[i] = Integer.valueOf(a1[i]).intValue() - 48;
		}

		char b1[] = string2.toCharArray();

		int b[] = new int[b1.length];
		for (int j = 0; j < b1.length; j++) {

			b[j] = Integer.valueOf(b1[j]).intValue() - 48;

		
		}

		add(a, b);

	}

	public static void add(int c[], int d[]) {

		int temp = 0;
		int e[] = new int[50];
		int c1 = c.length - 1, d1 = d.length - 1, e1 = e.length - 1;

		while (c1 >= 0 && d1 >= 0) {
			if (c[c1] + d[d1] > 9) {
				e[e1] = c[c1] + d[d1] - 10 + temp;
				temp = 1;
			} else {
				e[e1] = c[c1] + d[d1] + temp;
				temp=0;
			}
			c1--;
			d1--;
			e1--;
		}
		while (c1 >= 0 || d1 >= 0) {
			if (c1 >= 0) {
				e[e1] = c[c1] + temp;
				temp=0;
			} else {
				e[e1] = d[d1] + temp;
				temp=0;
			}

			c1--;
			d1--;
			e1--;
		}

		
		System.out.println();
		String sum=Arrays.toString(e);
		System.out.println(sum);

	}

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