How to decode larger integers in PHP

藏色散人
Release: 2023-04-04 14:08:01
Original
3123 people have browsed it

PHP decoding larger integers is also one of the more common test points during the PHP interview process. Then such an implementation is also very simple, we can decode it through the json_decode function.

How to decode larger integers in PHP

# Let’s use a simple code example to introduce how PHP decodes large integers.

For example, a large integer example is as follows:

{“number”:123456789012345678901234567890}
Copy after login

The PHP code is as follows:

<?php
$json = &#39;{"number": 123456789012345678901234567890}&#39;;
var_dump(json_decode($json));
Copy after login

The print result is as follows:

How to decode larger integers in PHP

json_decode function represents decoding a string in JSON format, accepting a JSON-encoded string and converting it into a PHP variable.

json_decode syntax:

mixed json_decode ( string $json [, bool $assoc = false [, int $depth = 512 [, int $options = 0 ]]] )
Copy after login

The parameter json represents the json string format string to be decoded. This function can only handle UTF-8 encoded data.

assoc, when this parameter is TRUE, array will be returned instead of object.

depth, specifies the recursion depth.

options, mask options for JSON decoding. There are now two supported options. The first one is JSON_BIGINT_AS_STRING, which is used to convert large integers into strings instead of the default float type. The second is JSON_OBJECT_AS_ARRAY, which has the same effect as setting assoc to TRUE.

This article is an introduction to the method of decoding large integers in PHP. It is very simple. I hope it will be helpful to friends in need!


The above is the detailed content of How to decode larger integers in PHP. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!