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How to write the url path of ajax?

藏色散人
Release: 2019-05-06 11:56:54
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How to write the url path of ajax?

How to write the url path of ajax?

For example, your page path is: http://localhost:8080/projectname/resource/index.html

The .do added at the end of the url request is for the server to distinguish whether the request is a static resource or a static resource. servlet request (.do followed by is a servlet request)

1. You can start with "/" relative to the root directory of the website (the root directory refers to the root directory of the server, not the root directory of your project)

$.ajax({
    url:"/getData.do"
})
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The requested path is:

http://localhost:8080/getData.do
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2. "../" indicates the upper-level directory of the page directory

$.ajax({
    url:"../getData.do" 
})
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The requested path is:

http://localhost:8080/projectname/getData.do
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Copy after login

3. The root path of the project

$.ajax({
    url:"getdata.do" 
})
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and the requested path is:

http://localhost:8080/projectname/getData.do
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Copy after login

4. The full path

$.ajax({
    url:"http://localhost:8080/projectname/getdata.do" 
})
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and the requested path is:

http://localhost:8080/projectname/getdata.do
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springMVC If The request mapping is written like this

How to write the url path of ajax?

If we want to request the register method, the url: ../user/register.do is written like this

Because the page path That's it

http://localhost:8080/projectname/resource/index.html
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Just let the servlet mapping request follow the project path

http://localhost:8080/projectname.

The final requested path is

http://localhost:8080/projectname/user/register.do
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