How to delete the element with specified index in list

There are three ways to delete an element in the list

1.remove: Delete a single element, delete the first element that meets the conditions, delete by value

Example:

>>> str=[1,2,3,4,5,2,6]
>>> str.remove(2)
>>> str
[1, 3, 4, 5, 2, 6]

2.pop: Delete single or multiple elements, delete bitwise (delete based on index)

>>> str=[0,1,2,3,4,5,6]
>>> str.pop(1)   #pop删除时会返回被删除的元素
>>> str
[0, 2, 3, 4, 5, 6]
>>> str2=['abc','bcd','dce']
>>> str2.pop(2)
'dce'
>>> str2
['abc', 'bcd']

3.del: It is based on the index (where the element is) position) to delete

Example:

>>> str=[1,2,3,4,5,2,6]
>>> del str[1]
>>> str
[1, 3, 4, 5, 2, 6]
>>> str2=['abc','bcd','dce']
>>> del str2[1]
>>> str2
['abc', 'dce']

In addition, del can also delete values ​​within the specified range.

>>> str=[0,1,2,3,4,5,6]
>>> del str[2:4]  #删除从第2个元素开始，到第4个为止的元素(但是不包括尾部元素)
>>> str
[0, 1, 4, 5, 6]

del can also delete the entire data object (list, collection, etc.)

>>> str=[0,1,2,3,4,5,6]
>>> del str
>>> str         #删除后，找不到对象
 
Traceback (most recent call last):
  File "<pyshell#27>", line 1, in <module>
    str
NameError: name &#39;str&#39; is not defined

Note: del deletes the reference (variable) instead of deleting the object (data). The object is collected by the automatic garbage collection mechanism (GC) deleted.

Supplement: Disguised method of deleting elements

s1=(1,2,3,4,5,6)
s2=(2,3,5)
s3=[]
for i in s1:
if i not in s2:
    s3.append(i)
print 's1-1:',s1
s1=s3
print 's2:',s2
print 's3:',s3
print 's1-2:',s1

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