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How to get name with jquery

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Release: 2019-05-29 10:35:47
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jquery searches based on the name attribute

How to get name with jquery

$("div[id]") //选择所有含有id属性的div元素 
$("input[name='keleyicom']") //选择所有的name属性等于'keleyicom'的input元素 

$("input[name!='keleyicom']") //选择所有的name属性不等于'keleyicom'的input元素 

$("input[name^='keleyi']") //选择所有的name属性以'keleyi'开头的input元素 
$("input[name$='keleyi']") //选择所有的name属性以'keleyi'结尾的input元素 
$("input[name*='keleyi']") //选择所有的name属性包含'keleyi'的input元素 

$("input[id][name$='keleyi']") //可以使用多个属性进行联合选择,该选择器是得到所有的含有id属性并且那么属性以keleyi结尾的元素
根据name取值:  

$("input[name='mobile']").val()
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Traverses based on the name value:

$("input[name='mobile']").each(  
    function(){  
   
    alert($(this).val());  
}  
)
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Take out the input in the form:

<script type="text/javascript" language="JavaScript" charset="UTF-8">    
$(document).ready(function(){    
var a=$("form input");    
$.each(    
    a,    
function(name,object){    
alert(name+":"+$(object).val());    
}    
);    
});    
</script>   
//得到值(多个的情况):  
$("input[name='mobile']")[0].value  

$("input[name='mobile']").get(1).value
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-----jquery add and delete styles--------

//给一个标签添加样式:  
$("#id").addClass("style");  
//删除一个标签的样式:  
$("#id").removeClass("style");  
//注:"#id"  id是对应标签的id,style是对应css样式的名称  
//获取单选标签选中获得的值
$("input[name='xxxx']:checked").val();
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