php判断是否是整数的两种方法
May 20, 2016 pm 12:56 PM
php
php判断一个数字是否是整数,面试的时候遇到的。我写了两种方法,不知道还有没有额。
方法一:利用php自带的函数 is_int() 可以轻松判断出该数字是否是整数。
方法二:可以用四舍或者五入该数字,再与原数比较,比如floor(3.1)结果应该是3,此时显然3!=3.1,或者用ceil()函数也行,这样也能判断出是否为整数。
举例说明:
$a = 3.3;
//方法一
if(is_int($a)){
echo "$a 是整数!";
}else{
echo "$a 不是整数!";
}
//方法二
if(floor($a)==$a){
echo "$a 是整数!";
}else{
echo "$a 不是整数!";
}
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