How to sort a dictionary in python

How to sort a dictionary in python? Here are two different methods:

Method 1:

#使用sorted函数进行排序
'''
sorted(iterable,key,reverse)，sorted一共有iterable,key,reverse这三个参数;
其中iterable表示可以迭代的对象，例如可以是dict.items()、dict.keys()等
key是一个函数，用来选取参与比较的元素，reverse则是用来指定排序是倒序还是顺序，reverse=true则是倒序，
reverse=false时则是顺序，默认时reverse=false。
'''
#初始化字典
dict_data={6:9,10:5,3:11,8:2,7:6}

1. Sort the dictionary keys

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#对字典按键（key）进行排序（默认由小到大）
test_data_0=sorted(dict_data.keys())
#输出结果
print(test_data_0) #[3, 6, 7, 8, 10]
test_data_1=sorted(dict_data.items(),key=lambda x:x[0])
#输出结果
print(test_data_1) #[(3, 11), (6, 9), (7, 6), (8, 2), (10, 5)]

2. Sort the dictionary by value(value)

#对字典按值（value）进行排序（默认由小到大）
test_data_2=sorted(dict_data.items(),key=lambda x:x[1])
#输出结果
print(test_data_2) #[('8', 2), ('10', 5), ('7', 6), ('6', 9), ('3', 11)]
test_data_3=sorted(dict_data.items(),key=lambda x:x[1],reverse=True)
#输出结果
print(test_data_3) #[('3', 11), ('6', 9), ('7', 6), ('10', 5), ('8', 2)]

Method 2:

import operator
#初始化字典
dict_data={6:9,10:5,3:11,8:2,7:6}
#按键（key）进行排序
test_data_4=sorted(dict_data.items(),key=operator.itemgetter(0))
test_data_5=sorted(dict_data.items(),key=operator.itemgetter(0),reverse=True)
print(test_data_4) #[(3, 11), (6, 9), (7, 6), (8, 2), (10, 5)]
print(test_data_5) #[(10, 5), (8, 2), (7, 6), (6, 9), (3, 11)]
#按值（value）进行排序
test_data_6=sorted(dict_data.items(),key=operator.itemgetter(1))
test_data_7=sorted(dict_data.items(),key=operator.itemgetter(1),reverse=True)
print(test_data_6) #[(8, 2), (10, 5), (7, 6), (6, 9), (3, 11)]
print(test_data_7) #[(3, 11), (6, 9), (7, 6), (10, 5), (8, 2)]

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