How to reverse integer output in python

Given a 32-bit signed integer, return its inverted integer

Example 1:
 
Input: 123
Output: 321

Example 2:
 
Input: -123
Output: -321

Example 3:
 
Input: 120
Output: 21

Assume that the size range of the integer is:, if the inverted integer overflows, then Return 0.

1: The normal integer method is implemented by using the remainder*10 accumulation method. It should be noted that Python uses a "round down" mechanism for integer division, so positive numbers and negative numbers must be operated differently.

def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        num = 0
        if x == 0:
            return 0
        if x < 0:
            x = -x
            while x != 0:
                num = num*10 + x%10
                x = x/10
            num = -num
        else:
            while x != 0:
                num = num*10 + x%10
                x = x/10
            
        if num>pow(2,31)-1 or num < pow(-2,31):
            return 0
        return num

2: Convert an integer to a string, reverse the string, and then convert it to an integer again

def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        plus_minus = ""
        reverse_x = ""
        if x<0:
            plus_minus = "-"
            x = -x
        for i in str(x):
            reverse_x = i + reverse_x
        reverse_x = plus_minus +reverse_x
        if int(reverse_x)>pow(2,31)-1 or int(reverse_x)<pow(-2,31):
            return 0

Recommended related tutorials: Python video tutorial

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