nth-of-type在选择class的时候需要注意的一个小问题 - Canrz
查了下w3和MDN的手册，没发现有这个说明，写篇随笔记下。
1、.class:nth-of-type(n)在选择class的时候，如果在class前面插入x个同类型标签，n需要加上x
<!DOCTYPE html>
<html>
<meta http-equiv="Content-Type" content="text/html;charset=UTF-8">
<head>
<style>
* {padding: .5em;}
.para:nth-of-type(1) {background-color: red;}
</style>
</head>
<body>
<p class="para">我是第1个p.para标签</p>
<p class="para">我是第2个p.para标签</p>
</body>
</html>
当在第1个p.para前面插入一个p时:
<p>我是一个普通的p标签</p>
<p class="para">我是第1个p.para标签</p>
<p class="para">我是第2个p.para标签</p>
此时.para:nth-of-type(2)才会是第一个p.para样式生效，jQuery选择器同理：
2、如果多个标签具有相同class，.class:nth-of-type(n)选择class的时候会全部选中所有标签的第n个class元素，jQuery只选择第一个标签的第n个class元素
<div class="para">我是第1个div.para标签</div>
<div class="para">我是第2个div.para标签</div>
<div>我是一个普通的div标签</div>
<section class="para">我是第1个section.para标签</section>
<section class="para">我是第2个section.para标签</section>
<section>我是一个普通的section标签</section>
<p class="para">我是第1个p.para标签</p>
<p class="para">我是第2个p.para标签</p>
<p>我是一个普通的p标签</p>
建议添加样式时使用tag:nth-of-type(n)或者tag.class:nth-of-type(n)筛选元素
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