PHP determines whether a year is a leap year
Determining leap years: (Recommended learning: PHP programming from entry to proficiency)
①. An ordinary year is a leap year if it is divisible by 4 but not divisible by 100. (For example, 2004 is a leap year, and 1900 is not a leap year)
②. A leap year is a century year that is divisible by 400 but not divisible by 3200. (For example, 2000 is a leap year, and 3200 is not a leap year)
Code:
<html>
<head>
<meta charset="UTF-8" />
<title>闰年判断</title>
</head>
<?php
$year = $_GET["year"];
if (isset($_GET["year"])) {
if (is_numeric($year)) {
if ($year % 100 == 0) { //判断世纪年
if ($year % 400 == 0 && $year % 3200 != 0) {
echo "世纪年" . $year . "是闰年!"; //世纪年里的闰年
} else {
echo "世纪年" . $year . "不是闰年!";
}
} else { //剩下的就是普通年了
if ($year % 4 == 0 && $year % 100 != 0) {
echo "普通年" . $year . "是闰年!"; //普通年里的闰年
} else {
echo "普通年" . $year . "不是闰年!";
}
}
} else
$msg = "请输入正确的格式";
}
?>
<body>
<form name=rn method='get'>
<b>请输入年：</b>
<input type="text" name=year>
<input type="submit" name=sub value="查询">
<?php
echo $msg;
?>
</form>
</body>
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