Java determines whether it is a palindrome number

java determines whether it is a palindrome number

The following introduces a simple judgment method, which has been explained in the specific implementation code:

import java.util.*;
public class StringBufferDemo {
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        //从键盘上输入一个字符串str
        String str = "";
        System.out.println("请输入一个字符串:");
        Scanner in = new Scanner(System.in);
        str = in .nextLine();
        //根据字符串创建一个字符缓存类对象sb
        StringBuffer sb = new StringBuffer(str);
        //将字符缓存中的内容倒置
        sb.reverse();
        //计算出str与sb中对应位置字符相同的个数n
        int n = 0;
        for (int i = 0; i < str.length(); i++) {
            if (str.charAt(i) == sb.charAt(i))
                n++;
        }
        //如果所有字符都相等，即n的值等于str的长度，则str就是回文。
        if (n == str.length())
            System.out.println(str + "是回文!");
        else
            System.out.println(str + "不是回文!");
    }
}

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