How to determine whether a string is a number in java
用JAVA自带的函数
public static boolean isNumericZidai(String str) { for (int i = 0; i < str.length(); i++) { System.out.println(str.charAt(i)); if (!Character.isDigit(str.charAt(i))) { return false; } } return true; }
其中Character.isDigit方法:确定或判断指定字符是否是一个数字。
测试方法:
public static void main(String[] args) { double aa = -19162431.1254; String a = "-19162431.1254"; String b = "-19162431a1254"; String c = "中文"; System.out.println(isNumericzidai(Double.toString(aa))); System.out.println(isNumericzidai(a)); System.out.println(isNumericzidai(b)); System.out.println(isNumericzidai(c)); }
结果显示:
false false false false
这种方法显然不能判断 负数。
用正则表达式
/** * 匹配是否为数字 * @param str 可能为中文,也可能是-19162431.1254,不使用BigDecimal的话,变成-1.91624311254E7 * @return * @date 2016年11月14日下午7:41:22 */ public static boolean isNumeric(String str) { // 该正则表达式可以匹配所有的数字 包括负数 Pattern pattern = Pattern.compile("-?[0-9]+(\\.[0-9]+)?"); String bigStr; try { bigStr = new BigDecimal(str).toString(); } catch (Exception e) { return false;//异常 说明包含非数字。 } Matcher isNum = pattern.matcher(bigStr); // matcher是全匹配 if (!isNum.matches()) { return false; } return true; }
使用org.apache.commons.lang
public static boolean isNumeric(String str)Checks if the String contains only unicode digits. A decimal point is not a unicode digit and returns false. null will return false. An empty String ("") will return true. StringUtils.isNumeric(null) = false StringUtils.isNumeric("") = true StringUtils.isNumeric(" ") = false StringUtils.isNumeric("123") = true StringUtils.isNumeric("12 3") = false StringUtils.isNumeric("ab2c") = false StringUtils.isNumeric("12-3") = false StringUtils.isNumeric("12.3") = false Parameters: str - the String to check, may be null Returns: true if only contains digits, and is non-null
更多java知识请关注java基础教程。
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