Home Java JavaInterview questions Java multithreading and concurrency interview questions (Question 4, with answers)

Java multithreading and concurrency interview questions (Question 4, with answers)

Nov 26, 2019 pm 05:17 PM
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Java multithreading and concurrency interview questions (Question 4, with answers)

4. ConcurrentLinkedQueue non-blocking unbounded linked list queue

ConcurrentLinkedQueue is a thread-safe queue, implemented based on the linked list structure, and is an unbounded queue. Theoretically, the length of the queue can be expanded infinitely.

Like other queues, ConcurrentLinkedQueue also uses the first-in-first-out (FIFO) enqueuing rule to sort elements. (Recommended study: java interview questions)

When we add elements to the queue, the newly inserted element will be inserted into the end of the queue; and when we get an element, it will Removed from the head of the queue.

Because ConcurrentLinkedQueue is a linked list structure, when entering the queue, the inserted elements are extended backwards in order to form a linked list; when dequeuing, they are obtained starting from the first element of the linked list and increasing in sequence;

It is worth noting that when using ConcurrentLinkedQueue, if it involves judging whether the queue is empty, remember not to use size()==0, because in the size() method, the entire linked list is traversed. In practice, when there are many queue elements, the size() method consumes a lot of performance and time. You can simply use isEmpty() to determine if the queue is empty.

public class ConcurrentLinkedQueueTest {<br/>    public static int threadCount = 10;<br/>    public static ConcurrentLinkedQueue<String> queue = new ConcurrentLinkedQueue<String>();<br/>    static class Offer implements Runnable {<br/>        public void run() {<br/>            //不建议使用 queue.size()==0,影响效率。可以使用!queue.isEmpty()<br/>            if (queue.size() == 0) {<br/>                String ele = new Random().nextInt(Integer.MAX_VALUE) + "";<br/>                queue.offer(ele);<br/>                System.out.println("入队元素为" + ele);<br/>            }<br/>        }<br/>    }<br/>    static class Poll implements Runnable {<br/>        public void run() {<br/>            if (!queue.isEmpty()) {<br/>                String ele = queue.poll();<br/>                System.out.println("出队元素为" + ele);<br/>            }<br/>        }<br/>    }<br/>    public static void main(String[] agrs) {<br/>        ExecutorService executorService = Executors.newFixedThreadPool(4);<br/>        for (int x = 0; x < threadCount; x++) {<br/>            executorService.submit(new Offer());<br/>            executorService.submit(new Poll());<br/>        }<br/>        executorService.shutdown();<br/>    }<br/>}<br/>
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One output:

入队元素为313732926<br/>出队元素为313732926<br/>入队元素为812655435<br/>出队元素为812655435<br/>入队元素为1893079357<br/>出队元素为1893079357<br/>入队元素为1137820958<br/>出队元素为1137820958<br/>入队元素为1965962048<br/>出队元素为1965962048<br/>出队元素为685567162<br/>入队元素为685567162<br/>出队元素为1441081163<br/>入队元素为1441081163<br/>出队元素为1627184732<br/>入队元素为1627184732<br/>
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ConcurrentLinkedQuere class diagram

Java multithreading and concurrency interview questions (Question 4, with answers)

As shown in the figure There are two volatile Node nodes in ConcurrentLinkedQueue, which are used to store the first and last nodes of the list. The head node stores the node whose first item in the linked list is null, and the tail does not always point to the last node.

The Node node maintains a variable item internally to store the value of the node, and next is used to store the next node, thus linking it to a one-way unbounded list.

public ConcurrentLinkedQueue(){<br/>    head=tail=new Node<E>(null);<br/>}<br/>
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When the above code is initialized, an empty node with item NULL will be constructed as the head and tail nodes of the linked list.

Offer operation The offer operation is to add an element at the end of the linked list.

Let’s take a look at the implementation principle.

public boolean offer(E e) {<br/>    //e 为 null 则抛出空指针异常<br/>    checkNotNull(e);<br/>    //构造 Node 节点构造函数内部调用 unsafe.putObject,后面统一讲<br/>    final Node<E> newNode = new Node<E>(e);<br/>    //从尾节点插入<br/>    for (Node<E> t = tail, p = t; ; ) {<br/>        Node<E> q = p.next;<br/>        //如果 q=null 说明 p 是尾节点则插入<br/>        if (q == null) {<br/>            //cas 插入(1)<br/>            if (p.casNext(null, newNode)) {<br/>                //cas 成功说明新增节点已经被放入链表,然后设置当前尾节点(包含 head,1,3,5.。。个节点为尾节点)<br/>                if (p != t)// hop two nodes at a time<br/>                    casTail(t, newNode); // Failure is OK. return true;<br/>            }<br/>            // Lost CAS race to another thread; re-read next<br/>        } else if (p == q)//(2)<br/>            //多线程操作时候,由于 poll 时候会把老的 head 变为自引用,然后 head 的 next 变为新 head,所以这里需要<br/>            //重新找新的 head,因为新的 head 后面的节点才是激活的节点<br/>            p = (t != (t = tail)) ? t : head;<br/>        else<br/>            // 寻找尾节点(3)<br/>            p = (p != t && t != (t = tail)) ? t : q;<br/>    }<br/>}<br/>
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From the constructor, we know that there is a sentinel node with null item at the beginning, and both head and tail point to this node.

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