Java method to determine whether it is json

Java method to determine whether it is in json format: (Recommended: java video tutorial)

json format: {"name":"Michael" ,"age":24,"birthday":"2018-09-09"};

private boolean isjson(String str){
    try {
        JSONObject jsonStr= JSONObject.parseObject(string);
        return  true;
    } catch (Exception e) {
        return false;
    }
}

JSONObject.parseObject(String str) is a method in fastjson.

fastjson is a high-performance JSON parser and generator implemented in Java language, developed by engineers from Alibaba. Its main features are:

① Fast: fastjson uses an original algorithm to increase the speed of parse to the extreme, surpassing all Java-based json libraries, including jackson, which was once known as the fastest;

② Powerful: Fastjson fully supports the standard of http://json.org (also one of the reference implementations included on Google’s official website); supports various JDK types; including basic types, JavaBean, Collection, Map, Enum, generics, etc.;

③Zero dependency: Does not depend on any other class library except JDK, can run directly on Java SE 5.0 or above; supports Android; open source (Apache 2.0).

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