Java method to determine whether a time is today
java determines whether the time is today:
public class Test { /** * java 判断一个时间是不是今天的时间范围内 * @param args */ public static void main(String[] args) { String time = "2017-09-27 11:20:45"; DateTimeFormatter dtf = DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss"); LocalDateTime localTime = LocalDateTime.parse(time, dtf); LocalDateTime startTime = LocalDate.now().atTime(0, 0, 0); LocalDateTime endTime = LocalDate.now().atTime(23, 59, 59); //如果小于今天的开始日期 if (localTime.isBefore(startTime)) { System.out.println("时间是过去"); } //如果大于今天的开始日期,小于今天的结束日期 if (localTime.isAfter(startTime) && localTime.isBefore(endTime)) { System.out.println("时间是今天"); } //如果大于今天的结束日期 if (localTime.isAfter(endTime)) { System.out.println("时间是未来"); } } }
java.time.LocalTime.isAfter(LocalTime other) method checks whether this time is after the specified time.
Declaration:
public boolean isAfter(LocalTime other)
Parameters: other - Another time to compare, not null.
Return value: true if this time is after the specified time.
java.time.LocalTime.isBefore(LocalTime other) method checks whether this time is before the specified time.
Declaration:
public boolean isBefore(LocalTime other)
Parameters: other - Another time to compare, not null.
Return value: true if this time is earlier than the specified time.
For more java knowledge, please pay attention to the java basic tutorial column.
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