Java method to verify whether it is a number:
Method 1: Use JAVA’s own function
public static boolean isNumeric(String str){ for (int i = str.length();--i>=0;){ if (!Character.isDigit(str.charAt(i))){ return false; } } return true; }
Method 2:
/* * 判断是否为整数 * @param str 传入的字符串 * @return 是整数返回true,否则返回false */ public static boolean isInteger(String str) { Pattern pattern = Pattern.compile("^[-\+]?[\d]*$"); return pattern.matcher(str).matches(); }
Method three:
public static boolean isNumeric(String str){ Pattern pattern = Pattern.compile("[0-9]*"); return pattern.matcher(str).matches(); }
Method four:
public final static boolean isNumeric(String s) { if (s != null && !"".equals(s.trim())) return s.matches("^[0-9]*$"); else return false; }
Method five: use ascii code
public static boolean isNumeric(String str){ for(int i=str.length();--i>=0;){ int chr=str.charAt(i); if(chr<48 || chr>57) return false; } return true; }
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