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Java method to verify whether it is a number

Dec 14, 2019 am 09:59 AM
java

Java method to verify whether it is a number

Java method to verify whether it is a number:

Method 1: Use JAVA’s own function

public static boolean isNumeric(String str){
for (int i = str.length();--i>=0;){
if (!Character.isDigit(str.charAt(i))){
return false;
}
}
return true;
}
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Method 2:

/*
* 判断是否为整数
* @param str 传入的字符串
* @return 是整数返回true,否则返回false
*/
public static boolean isInteger(String str) {
Pattern pattern = Pattern.compile("^[-\+]?[\d]*$");
return pattern.matcher(str).matches();
}
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Method three:

public static boolean isNumeric(String str){
Pattern pattern = Pattern.compile("[0-9]*");
return pattern.matcher(str).matches();
}
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Method four:

public final static boolean isNumeric(String s) {
if (s != null && !"".equals(s.trim()))
return s.matches("^[0-9]*$");
else
return false;
}
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Method five: use ascii code

public static boolean isNumeric(String str){
for(int i=str.length();--i>=0;){
int chr=str.charAt(i);
if(chr<48 || chr>57)
return false;
}
return true;
}
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