Question:
When uploading files, it is necessary to verify whether the uploaded files are legal. How to identify file camouflage?
A simple test: change the txt file suffix directly to jpg; upload
<!DOCTYPE html> <html> <title>test</title> <body> <form enctype="multipart/form-data" action="test.php" method="POST"> <!-- MAX_FILE_SIZE must precede the file input field --> <input type="hidden" name="MAX_FILE_SIZE" value="102400" /> <!-- Name of input element determines name in $_FILES array --> Send this file: <input name="userfile" type="file" /> <input type="submit" value="Send File" /> </form> </body> </html>
1. Get the file suffix through $_FILES['userfile']['type'];
$data = $_FILES['userfile']; var_dump($data); /**结果**/ /* array(5) { ["name"]=> string(8) "test.jpg" ["type"]=> string(10) "image/jpeg" ["tmp_name"]=> string(26) "/private/var/tmp/phpfyE3EC" ["error"]=> int(0) ["size"]=> int(19) } */
Not detected;
2. Use the pathinfo() function to obtain file path information
$data = $_FILES['userfile']; // var_dump($data); var_dump(pathinfo($data['name'])); /**结果**/ /* array(4) { ["dirname"]=> string(1) "." ["basename"]=> string(8) "test.jpg" ["extension"]=> string(3) "jpg" ["filename"]=> string(4) "test" } */
Not detected;
3. PHP extension fileinfo (needs to be installed and enabled)
$data = $_FILES['userfile']; $filename = $data['tmp_name']; $finfo = finfo_open(FILEINFO_MIME_TYPE);//返回 mime 类型。 自 PHP 5.3.0 可用。 $mimetype = finfo_file($finfo, $filename); finfo_close($finfo); var_dump($mimetype); /**结果**/ //string(10) "text/plain"
Yes! Can! Can! It is detected that the file mime type is not a jpg!
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