C language to find the average of n numbers:
Recommended: "c Language Tutorial"
#include<stdio.h> int main(void) { int a[100] = { NULL };//初始化数组元素 int i = 0, n;//定义循环变量和正整数变量n float sum = 0.0;//定义和变量为float型,注意计算的数据类型 float average = 0.0;//定义平均数变量为float型,注意计算的数据类型 printf("Please input n (n<100) :"); scanf("%d", &n);//输入正整数n printf("Please input %d integers:", n);//提示输入几个正整数 for (i = 0; i < n; i++)//循环输入元素 { scanf("%d", &a[i]);//输入整形变量 sum += a[i];//循环输入的时候同时进行求和 } //for (i = n - 1; i >= 0; i--) printf("the a[n] number: ");//倒叙输出数组元素 for (i = 0; i < n; i++)//循环输入元素 printf("%d ", a[i]);//倒叙输出数组元素 printf("\n"); average = sum / (float)n;//注意不同类型之间的计算,这里加了类型强制转换 printf("averge=%.2f\n", average);//输出平均数 return 0; }
The program running results are as follows:
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