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How to find the average of n numbers in C language?

Mar 05, 2020 pm 01:24 PM
c language

How to find the average of n numbers in C language?

C language to find the average of n numbers:

Recommended: "c Language Tutorial"

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#include<stdio.h>

int main(void)

{

int a[100] = { NULL };//初始化数组元素

int i = 0, n;//定义循环变量和正整数变量n

float sum = 0.0;//定义和变量为float型,注意计算的数据类型

float average = 0.0;//定义平均数变量为float型,注意计算的数据类型

printf("Please input n (n<100) :");

scanf("%d", &n);//输入正整数n

printf("Please input %d integers:", n);//提示输入几个正整数

for (i = 0; i < n; i++)//循环输入元素

{

scanf("%d", &a[i]);//输入整形变量

sum += a[i];//循环输入的时候同时进行求和

}

//for (i = n - 1; i >= 0; i--)

printf("the a[n] number: ");//倒叙输出数组元素

for (i = 0; i < n; i++)//循环输入元素

printf("%d ", a[i]);//倒叙输出数组元素

printf("\n");

average = sum / (float)n;//注意不同类型之间的计算,这里加了类型强制转换

printf("averge=%.2f\n", average);//输出平均数

return 0;

}

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The program running results are as follows:

How to find the average of n numbers in C language?

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