How to implement message board function in PHP
How to implement the message board function in PHP
First create a message table, whose main fields include the name of the sender, message content, and message delivery Time;
SQL:
CREATE TABLE `guanhui`.`message` ( `id` INT(10) NOT NULL AUTO_INCREMENT COMMENT '消息ID' , `sender` VARCHAR(60) NOT NULL COMMENT '发送者' , `content` TEXT NOT NULL COMMENT '消息内容' , `send_time` INT(10) UNSIGNED NOT NULL DEFAULT '0' COMMENT '发送时间' , PRIMARY KEY (`id`) ) ENGINE = MyISAM;
Then create a form on the front end and query the message messages for list display;
Form HMTL:
<form action="./send_message.php" method="POST"> <input type="text" name="sender" placeholder="你的昵称"> <textarea rows="4" name="content" placeholder="留言内容"></textarea> <button type="submit">发送</button> </form>
Display list:
<?php //链接数据库 $conn = mysql_connect("loclhost:3306","root","root"); //判断错误函数 if(!$conn){ die(mysql_error()); } //选择数据库 mysql_query("use message",$conn); //设定字符集编码 mysql_query("set names utf8",$conn); //查询语句 $sql = "select * from message"; //执行语句 $res = mysql_query($sql); //建立一个空数组 $data = array(); //执行循环 while($row = mysql_fetch_assoc($res)){ $data[] = $row; } ?> <table> <tr> <th>ID</th> <th>Name</th> <th>Sender</th> <th class="content">Content</th> <th>操作</th> </tr> <?php foreach($data as $k=>$v){?> <tr> <td><?=$v['id']?></td> <td><?=$v['name']?></td> <td><?=$v['sender']?></td> <td><?=$v['content']?></td> <td> <a href="./update.php?id=<?=$v['id']?>">修改</a> <a href="./del.php?id=<?=$v['id']?>">删除</a> </td> </tr> <?php }?> <table>
Finally, save the information submitted by the form to the database.
<?php //链接数据库 $conn = mysql_connect("loclhost:3306","root","root"); //判断错误函数 if(!$conn){ die(mysql_error()); } //选择数据库 mysql_query("use message",$conn); //设定字符集编码 mysql_query("set names utf8",$conn); //获取表单值 $name = $_POST['name']; $sender = $_POST['sender']; $content =$_POST['content']; //插入数据库语句 $sql = "insert into message(name,sender,content)values('$name','$sender','$content')"; //执行数据 $res = mysql_query($sql); //判断结果 if($res){ echo "增加成功"; }else{ die("增加失败".mysql_error()); }
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