Home > Java > javaTutorial > What does java.lang.NullPointerException mean?

What does java.lang.NullPointerException mean?

Guanhui
Release: 2020-06-04 14:03:44
Original
75532 people have browsed it

What does java.lang.NullPointerException mean?

What does java.lang.NullPointerException mean?

"java.lang.NullPointerException" mainly occurs at runtime. This exception belongs to a subclass of RuntimeException, so it is an exempt exception. When the application tries to use null where an object is required, This exception will be thrown.

Several reasons for "java.lang.NullPointerException"

1. The string variable is not initialized

2. Interface type objects are not initialized with a specific class, such as:

Map map // 会报错
Map map = new Map(); //则不会报错了
Copy after login

3. When the value of an object is empty, you do not judge it to be empty.

4. Comparison between strings and text. Text can be a string or an element of Enum. An exception will occur as follows

String str = null;
if(str.equals(“Test”)){
//这里的代码将不会被触发,因为会抛出java.lang.NullPointerException异常。
}
Copy after login

5. Prioritize using the String.valueOf() method instead of toString( )

When program code requires a string representation of an object, avoid using the object's toString method. If the reference of your object is equal to null, NullPointerException will be thrown. Use the static String.valueOf method. This method will not throw any exception and print "null"

6. The class is declared type, default class = null; In this way, the system can only give you a null pointer exception when calling the method in the class. Just instantiate it: class = new Class();

7. Return null, the method Do not define the return value as a general type, but use an array. In this way, if you want to return null, you can avoid many unnecessary NullPointerException

Recommended tutorial: "Java Tutorial"

The above is the detailed content of What does java.lang.NullPointerException mean?. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template