Home > Java > JavaBase > What is the storage type of args when passed into a function in Java?

What is the storage type of args when passed into a function in Java?

hzc
Release: 2020-06-17 16:49:14
Original
4482 people have browsed it

What is the storage type of args when passed into a function in Java?

#What is the storage type of args when passed into a function in Java?

Java1.5 adds new features: variable parameters:

Suitable for situations where the number of parameters is uncertain and the type is determined. Java treats variable parameters as an array.

Note: The variable parameter must be in the last item. When there are more than one variable parameters, one of them must not be the last item, so only one variable parameter is supported. Because the number of parameters is variable, when there are parameters of the same type behind them, Java cannot distinguish whether the incoming parameter belongs to the previous variable parameter or the following parameter, so it can only place the variable parameter in the last item.

Characteristics of variable parameters:

(1) can only appear at the end of the parameter list;

(2)...is located between the variable type and the variable name , with or without spaces before and after;

(3) When calling a method with variable parameters, the compiler implicitly creates an array for the variable parameters, and accesses the variable parameters in the form of an array in the method body .

public class Varable {
 public static void main(String [] args){
  System.out.println(add(2,3));
  System.out.println(add(2,3,5));
 }
 public static int add(int x,int ...args){
  int sum=x;
  for(int i=0;i<args.length;i++){
   sum+=args[i];
  }
  return sum;
 }
}
Copy after login

Recommended tutorial: "java tutorial"

The above is the detailed content of What is the storage type of args when passed into a function in Java?. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template