How to output a diamond shape composed of asterisks in python?

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Release: 2020-06-24 09:07:26
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How to output a diamond shape composed of asterisks in python?How does python output a diamond shape composed of asterisks?

Python method to output a diamond shape composed of asterisks:

Read an integer N, N is an odd number, and output a diamond shape composed of asterisk characters Triangle, requires: ‮‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‪‬‮‬‪‬‪‬‪‬‪‬‪‬‮‬‫‬‫‬

1 asterisk on line 1, 3 on line 2 1 asterisk, 5 asterisks on the 3rd line, and so on. Finally, n/2 has a total of n asterisks, and then decreases to an asterisk on n lines.

def printStar(intNum):
  s = "*"
  spaceLength = intNum
  blockCount = int(intNum/2+1)
 
  for i in range(spaceLength):
    result = s.rjust(blockCount)
    if i >= int(spaceLength/2):
      print(result)
      s = s[2:]
      blockCount -= 1
    else:
      print(result)
      s = s+(2*"*")
      blockCount += 1
 
def oddOReven(intNum):
 
  if intNum%2 == 0:
    print("please input a odd num data")
  else:
    printStar(intNum)
 
if __name__ == '__main__':
   
  while True:
    try:
      intNum = eval(input("please input a odd num data\n"))
      oddOReven(intNum)
    except BaseException as e:
      print("Please input as 1/2/3... Errorcode:%s" % e)
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How to output a diamond shape composed of asterisks in python?

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