How to implement image upload preview in PHP?-PHP Problem-php.cn

How to implement image upload preview in PHP?

Guanhui

Release： 2023-03-02 19:26:02

Original

3735 people have browsed it

How to implement image upload preview in PHP?

PHP How to implement image upload preview?

First listen to the onchange event of the input tag; then use AJAX to upload the file to the server; then receive the uploaded file in PHP and save the file; finally return the file access path, and Just use JS to render.

Sample code

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>上传头像</title>
<style type="text/css">
  *{
    font-family:"微软雅黑";}
  #zong{
    /*border:1px solid black;*/
    position:relative;
    width:52%;
    height:500x;
    left:24%}
  .nr{
    float:left;
    margin-right:30px;}
  #yl{width:240px; height:240px; background-size:240px 240px;}
  #file{width:240px; height:240px; float:left; opacity:0;}
</style>
</head>

<body>

<div id="zong">
<form id="sc" action="2.php" method="post" enctype="multipart/form-data" target="shangchuan">
  
  <input type="hidden" name="tp" value="" id="tp" />
  
  <div id="yl" style="background-image:url(./image/1.jpg)" class="nr">//头像显示的位置
    <input type="file" name="file" id="file" onchange="document.getElementById(&#39;sc&#39;).submit()" />
  </div>
  <div class="nr">
  </div> 
</form>

<iframe style="display:none" name="shangchuan" id="shangchuan">
</iframe>

</div>
</body>

<script type="text/javascript">

//回调函数,调用该方法传一个文件路径，改变背景图
function showimg(url)
{
  var div = document.getElementById("yl");
  div.style.backgroundImage = "url("+url+")";
  
  document.getElementById("tp").value = url;
}

</script>

</html>

Copy after login

<?php
session_start();
$uid = $_SESSION["uid"];
if($_FILES["file"]["error"])
{
  echo $_FILES["file"]["error"];
}
else
{
  if(($_FILES["file"]["type"]=="image/jpeg" || $_FILES["file"]["type"]=="image/png")&& $_FILES["file"]["size"]<1024000)
  {
    $fname = "./a/image/".date("YmdHis").$_FILES["file"]["name"];  //头像存储的路径
    
    $filename = iconv("UTF-8","gb2312",$fname);
    
    if(file_exists($filename))
    {
      echo "<script>alert(&#39;该文件已存在！&#39;);</script>";
    }
    else
    {
      move_uploaded_file($_FILES["file"]["tmp_name"],$filename);
      
      unlink($_POST["tp"]);
      echo "<script>parent.showimg(&#39;{$fname}&#39;);</script>";
    }
    
  }
}

Copy after login