How to use json method in php

In PHP, you can operate json through the "json_encode()" and "json_decode()" functions, whose syntax is "json_encode($arr);" and "json_decode($json)" respectively.

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Starting from version 5.2, PHP natively provides json_encode() and json_decode () function, the former is used for encoding and the latter is used for decoding.

json_encode()                                                                                                                                                                                                                                                     .

The code is as follows:

$arr = array ('a'=>'a','b'=>'b','c'='c','d'=>'d','e'='e');
echo json_encode($arr);

Output result:

json only accepts utf-8 encoded characters, and the parameters of json_encode() must be utf-8 encoded.

class person 
{ 
  public $name; 
  public $age; 
  public $height; 
  function __construct($name,$age,$height) 
  { 
    $this->name = $name; 
    $this->age = $age; 
    $this->height = $height;   
  }  
} 
$obj = new person("zhangsan",20,100); 
$foo_json = json_encode($obj); 
echo $foo_json;

Output results:

When the attributes in the class are private variables, they will not be output.

json_decode()

The code is as follows:

$json = '{"a":"hello","b":"world","c":"zhangsan","d":20,"e":170}';
var_dump(json_decode($json));

Output result:

Normally, json_decode() always returns a PHP object.

Converted to an array:

The code is as follows:

$json = '{"a":"hello","b":"world","c":"zhangsan","d":20,"e":170}';
var_dump(json_decode($json,ture));

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