Introduction to Go pointers

The following column will introduce Go pointers to you in the golang tutorial column. I hope it will be helpful to friends in need!

Combined with this example to analyze

The result:

Combined with the basis of the previous C language, Draw a picture to explain why the above values ​​appear. Let’s first check what these two operators are in Go.

①For all results with a

var a int = 1 defines a variable a with a value of 1, as shown in the following figure:

&a is the address that stores the value of a variable

*&a is a pointer to &a, *&a = a = 1

②All Result with b

var b *int = &a

Similar to C language int *b = &a Define a pointer b pointing to an integer variable, b points to the address of a

So:

b = &a = 0xc04203c1d0

&b = 0xc042058018 &b is the real address of the pointer variable b, which is the one after execution

*&b = *(&b) = b = &a = 0xc04203c1d0

*b = *&a = a = 1

③All results with c

As shown in the picture above:

var c **int = &b

actually defines a pointer variable pointing to an integer pointer

c = &b = 0xc042058018

*c = *&b = b = &a = 0xc04203c1d0

&c is the real address of this variable. What is shown here is the result of the operation 0xc042068020

* &c With experience, you can find that *& is eliminated directly = c = 0xc042058018

**c At first glance, you don’t know what it is. In fact, you can evaluate it through conversion

**c = **&b = *b = *&a = a = 1

***&*&*&*&*&c This can be eliminated first*& **c = 1

④About x

x = *b = *&a = a = 1

To summarize the above:

##&Passed The variable takes the address * by taking the address value

&a to get the address first, and then "* xxx address" gets the value of the variable at the address, that is, a

*& can offset

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