How to write python proxy ip

coldplay.xixi
Release: 2020-10-29 16:19:04
Original
12345 people have browsed it

python写代理ip的方法:首先创建代理ip对象,并定制一个opener对象;然后安装opener对象,以后的urlopen就一直使用这个代理地址。

How to write python proxy ip

python写代理ip的方法:

方法1:

先创建代理ip对象

proxy_support = urllib.request.ProxyHandler({'https':'117.64.149.137:808'})
Copy after login
Copy after login

定制一个opener对象

opener = urllib.request.build_opener(proxy_support)
Copy after login
Copy after login

安装这个opener对象,以后的urlopen就一直使用这个代理地址了

urllib.request.install_opener(opener)
Copy after login

发出请求时,就是用到这个代理地址了

html = urllib.request.urlopen('xxxxxxxxxx').read()
Copy after login

方法2:

先创建代理ip对象

proxy_support = urllib.request.ProxyHandler({'https':'117.64.149.137:808'})
Copy after login
Copy after login

定制一个opener对象

opener = urllib.request.build_opener(proxy_support)
Copy after login
Copy after login

这里可以直接使用opener对象发出请求

html = opener.open('xxxxxxxxx').read()
Copy after login

示例代码:

import urllib.request
#这一段三句话是为了请求时带上浏览器标识,因为有的网站看到是爬虫的标识直接返回403
#请求的网站不涉及到提交数据,所以没有给出data参数
url = 'https://whatismyipaddress.com/'
header = {'User-Agent':'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Safari/537.36'}
req = urllib.request.Request(url,headers=header)
#使用代理和还原不使用代理的方法
#if语句相当于一个开关,不要写成True
use_proxy = urllib.request.ProxyHandler({'https':'117.64.149.137:808'})
null_proxy = urllib.request.ProxyHandler()
if True:
    opener = urllib.request.build_opener(use_proxy)
else:
    opener = urllib.request.build_opener(null_proxy)
#根据上面的开关,安装的opener对象是否带有代理地址
urllib.request.install_opener(opener)
#获取返回结果
#同时可以使用html = opener.open(req).read()获取结果
html = urllib.request.urlopen(req).read()
#这网页返回页面的内容太多,在控制台不好查看,
#并且返回的内容是二进制格式,可以直接写入文件,当个网页查看
with open('E:\\whatismyip.html','wb') as file:
    file.write(html)
    print('OK')
Copy after login

相关免费学习推荐:python教程(视频)

The above is the detailed content of How to write python proxy ip. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template