About scalar type and return value type declaration in PHP7

                                                                                                                                                                                                              Scalar Type and Return Value Type Declaration.

A question: Are you writing code using new features?

Strict mode

php declare(strict_types=1);

Settings passed in Parameters, and return values ​​of outgoing parameters<div class="code" style="position:relative; padding:0px; margin:0px;"><pre class="brush:php;toolbar:false">class Person(){     public function name(string $name):string    {         return &quot;名称:&quot;.$name;     }     public function age(int $age):string    {         return &quot;年龄:&quot;.$age;     }}</pre><div class="contentsignin">Copy after login</div></div>

Custom return type

class Address(){
    public function getAddress(int $age):string    {
        return ['street'=>'street1','country'=>'china'];
    }}class Person(){

    public function name(string $name):string    {
        return "名称:".$name;
    }

    public function age(int $age):string    {
        return "年龄:".$age;
    }

    public function age(int $age):Address    {
        return new Address();
    }}

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