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PHP 验证身份证是否合法的函数_php技巧

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Release: 2016-05-25 17:00:29
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本文主要介绍了PHP验证身份证是否合法的函数。具有很好的参考价值,下面跟着小编一起来看下吧

话不多说,请看代码:

function is_idcard( $id )
{
  $id = strtoupper($id);
  $regx = "/(^\d{15}$)|(^\d{17}([0-9]|X)$)/";
  $arr_split = array();
  if(!preg_match($regx, $id))
  {
    return FALSE;
  }
  if(15==strlen($id)) //检查15位
  {
    $regx = "/^(\d{6})+(\d{2})+(\d{2})+(\d{2})+(\d{3})$/";
    @preg_match($regx, $id, $arr_split);
    //检查生日日期是否正确
    $dtm_birth = "19".$arr_split[2] . '/' . $arr_split[3]. '/' .$arr_split[4];
    if(!strtotime($dtm_birth))
    {
      return FALSE;
    }
    else
    {
      return TRUE;
    }
  }
  else //检查18位
  {
    $regx = "/^(\d{6})+(\d{4})+(\d{2})+(\d{2})+(\d{3})([0-9]|X)$/";
    @preg_match($regx, $id, $arr_split);
    $dtm_birth = $arr_split[2] . '/' . $arr_split[3]. '/' .$arr_split[4];
    if(!strtotime($dtm_birth)) //检查生日日期是否正确
    {
      return FALSE;
    }
    else
    {
      //检验18位身份证的校验码是否正确。
      //校验位按照ISO 7064:1983.MOD 11-2的规定生成,X可以认为是数字10。
      $arr_int = array(7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2);
      $arr_ch = array('1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2');
      $sign = 0;
      for ( $i = 0; $i < 17; $i++ )
      {
        $b = (int) $id{$i};
        $w = $arr_int[$i];
        $sign += $b * $w;
      }
      $n = $sign % 11;
      $val_num = $arr_ch[$n];
      if ($val_num != substr($id,17, 1))
      {
        return FALSE;
      }
      else
      {
        return TRUE;
      }
    }
  }
}
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