How to use the Round function in the access database:
(Related recommendations: access database tutorial)
Rounding The question
select round(83.124,2) as t from jqdltb
is displayed as: 83.12
select round(83.125,2) as t from jqdltb
is displayed as: 83.12
select round(83.126,2) as t from jqdltb
is displayed as: 83.13
The question is, how to round it into five What about rounding up?
The following is how to use this method to adjust to achieve rounding:
Use the int function and add 0.005, then *100, then /100
as shown below:
select int((83.121+0.005)*100)/100 as t from jqdltb
Displayed as: 83.12
select int((83.124+0.005)*100)/100 as t from jqdltb
Displayed as: 83.12
select int((83.125+0.005)*100)/100 as t from jqdltb
Displayed as: 83.13
select int((83.126+0.005)*100)/100 as t from jqdltb
Displayed as: 83.13
select int((83.129+0.005)*100)/100 as t from jqdltb
Displayed as: 83.13
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