jquery method to determine whether an element is visible

The implementation method of jquery to determine whether an element is visible: first select the element to be determined; then use "is()" with the ":visible" selector to determine whether it is visible. The syntax is such as "$(selector). is(":visible")".

The operating environment of this tutorial: windows7 system, jquery1.10.0 version, thinkpad t480 computer.

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jquery determines whether an element is visible

The method is very simple, select the element you want to judge, and then use is() with the :visible selector to judge whether it is visible; syntax $(selector).is(":visible").

is() method users check whether the selected element is equipped with a selector; the :visible selector selects each element that is currently visible.

Code to determine whether it is visible:

if($('#div').is(':visible')){
      //如果显示时。。。
}else{
      //如果隐藏时。。。
}

Description:

Elements other than the following situations are visible elements:

Set to display :none

type="hidden" form elements

Width and height are set to 0

Hidden parent elements (all child elements are hidden at the same time)

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