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How to modify pictures in php html

藏色散人
Release: 2023-03-08 12:16:01
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php html修改图片的方法:首先创建一个PHP示例文件;然后通过PHP正则提取html图片img标记中的任意属性;最后通过正则表达式修改替换图片指定属性即可。

How to modify pictures in php html

本文操作环境:windows7系统、PHP7.1版,DELL G3电脑。

php正则提取html图片(img)src地址与任意属性

简单版:

  <?php  
    header("Content-Type: text/html;charset=utf-8");  
      
    $str = &#39;<div class="ui-block-a" align="center">  
            <a href="online-39.html"><img class="lazy" width="131" height="177" src="http://www.smsyun.com/uploads/image/20140620/2014052010425.jpg"/>  
            <h3>2014年</h3></a>  
          </div>&#39;;  
      
    $imgpreg = "/<img (.*?) src=\"(.+?)\".*?>/";  
    preg_match($imgpreg,$str,$img);  
    $mycount=count($img)-1;  
     $imgval = $iim[$mycount];  
    if(!empty($imgval)){  
        echo $imgval;  
    }else{  
        echo &#39;no&#39;;  
    }  
    ?>
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详细版:

    <?php  
    /*PHP正则提取图片img标记中的任意属性*/  
    $str = &#39;<center><img src="/uploads/images/20100516000.jpg" height="120" width="120"><br />PHP正则提取或更改图片img标记中的任意属性</center>&#39;;  
      
    //1、取整个图片代码  
    preg_match(&#39;/<\s*img\s+[^>]*?src\s*=\s*(\&#39;|\")(.*?)\\1[^>]*?\/?\s*>/i&#39;,$str,$match);  
    echo $match[0];  
      
    //2、取width  
    preg_match(&#39;/<img.+(width=\"?\d*\"?).+>/i&#39;,$str,$match);  
    echo $match[1];  
      
    //3、取height  
    preg_match(&#39;/<img.+(height=\"?\d*\"?).+>/i&#39;,$str,$match);  
    echo $match[1];  
      
    //4、取src  
    preg_match(&#39;/<img.+src=\"?(.+\.(jpg|gif|bmp|bnp|png))\"?.+>/i&#39;,$str,$match);  
    echo $match[1];  
      
    /*PHP正则替换图片img标记中的任意属性*/  
    //1、将src="/uploads/images/20100516000.jpg"替换为src="/uploads/uc/images/20100516000.jpg")  
    print preg_replace(&#39;/(<img.+src=\"?.+)(images\/)(.+\.(jpg|gif|bmp|bnp|png)\"?.+>)/i&#39;,"\${1}uc/images/\${3}",$str);  
    echo "<hr/>";  
      
    //2、将src="/uploads/images/20100516000.jpg"替换为src="/uploads/uc/images/20100516000.jpg",并省去宽和高  
    print preg_replace(&#39;/(<img).+(src=\"?.+)images\/(.+\.(jpg|gif|bmp|bnp|png)\"?).+>/i&#39;,"\${1} \${2}uc/images/\${3}>",$str);  
    ?>
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