What is the cmd command to run an exe file?

The cmd command to run the exe file is "start [file name.exe]". The specific running method is: first click "Run" and enter "cmd" in the input field; then execute the "cd [file path]" command to jump to the folder where the exe program is located; finally execute "start [file name.exe] "Just give the order.

The operating environment of this tutorial: Windows 7 system, Dell G3 computer.

Open the Start menu on Windows. Click the Start button in the lower left corner of the desktop to open the Start menu.

#Enter and search for cmd in the Start menu. "Command Prompt" should appear at the top of the search results.

Click Command Prompt in the Start menu. A new Command Prompt window will open.

Enter cd [file path] in the window. You can use this command to navigate to the folder where the exe program you want to run is located.

#Find the path to the folder where the exe program is located. Open the folder where the program is located in a File Explorer window, and then copy or write down the file path in the address bar at the top of the window.

Replace [file path] in the command with the file path of the program. After redirecting to this path, you can execute the command here and run the exe file in the folder.

#Enter start [file name.exe] in the window. You can run programs in the current path with this command.

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