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How to find the absolute value in Go language

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Release: 2023-02-14 14:01:39
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In the Go language, you can use the abs() function in the math package to find the absolute value. The syntax format "math.Abs(x)" can return the absolute value of the parameter x; abs() function input The output value types are all "float64".

How to find the absolute value in Go language

The operating environment of this tutorial: Windows 10 system, GO 1.11.2, Dell G3 computer.

In the go language, you can use the abs() function in the math package to find the absolute value.

Syntax:

math.Abs(x float64)
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Return value:

  • Abs returns the absolute value of x.

Special cases are:

Abs(±Inf) = +Inf
Abs(NaN) = NaN
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Example

package main 

import (
    "fmt"
    "math"
)
func main() {
    x := math.Abs(-2)
    fmt.Printf("%.1f\n", x)
    y := math.Abs(2)
    fmt.Printf("%.1f\n", y)
}
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Extended information:

Golang Some commonly used methods under the math package

package main

import (
    "fmt"
    "math"

)
func main() {
    i := 1
    fmt.Println(math.Abs(float64(i)))         //取到绝对值
    fmt.Println(math.Ceil(3.8))             //向上取整
    fmt.Println(math.Floor(3.6))             //向下取整
    fmt.Println(math.Mod(11,3))         //取余数 11%3 效果一样
    fmt.Println(math.Modf(3.22))             //取整数跟小数
    fmt.Println(math.Pow(3,2))             //X 的 Y次方  乘方
    fmt.Println(math.Pow10(3))             //10的N次方 乘方
    fmt.Println(math.Sqrt(9))             //开平方  3
    fmt.Println(math.Cbrt(8))             //开立方  2
    fmt.Println(math.Pi)                     //π
    fmt.Println(math.Round(4.2))          //四舍五入

    fmt.Println(math.IsNaN(3.4))           //false   报告f是否表示一个NaN(Not A Number)值。
    fmt.Println(math.Trunc(1.999999))      //1    返回整数部分(的浮点值)。
    fmt.Println(math.Max(-1.3, 0))     //0   返回x和y中最大值
    fmt.Println(math.Min(-1.3, 0))    //-1.3  返回x和y中最小值
    fmt.Println(math.Dim(-12, -19))   //7 函数返回x-y和0中的最大值
    fmt.Println(math.Dim(-12, 19))    //0 函数返回x-y和0中的最大值
    fmt.Println(math.Cbrt(8))             //2  返回x的三次方根
    fmt.Println(math.Hypot(3, 4))     //5  返回Sqrt(p*p + q*q)
    fmt.Println(math.Pow(2, 8))       //256  返回x^y

}
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Result

1
4
3
2
3 0.2200000000000002
9
1000
3
2
3.141592653589793
4
false
1
0
-1.3
7
0
2
5
256
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Recommended learning:Golang tutorial

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