php unset is a function used to destroy a given variable. Its usage syntax is "void unset (mixed $var [, mixed $... ])", and its parameter "$var" means to destroy Variables.
The operating environment of this article: windows7 system, PHP7.1 version, DELL G3 computer
What does php unset mean?
The unset() function is used to destroy the given variable.
Syntax
void unset ( mixed $var [, mixed $... ] )
Parameter description:
$var: Variable to be destroyed.
Return value
No return value.
Example
<?php // 销毁单个变量 unset ($foo); // 销毁单个数组元素 unset ($bar['quux']); // 销毁一个以上的变量 unset($foo1, $foo2, $foo3); ?>
If you unset() a global variable in a function, only the local variable will be destroyed, and the variables in the calling environment will maintain the same value before calling unset().
Example
<?php function destroy_foo() { global $foo; unset($foo); } $foo = 'bar'; destroy_foo(); echo $foo; ?>
The output result is:
bar
If you want to unset() a global variable in the function, you can use the $GLOBALS array to achieve this:
Example
<?php function foo() { unset($GLOBALS['bar']); } $bar = "something"; foo(); ?>
If you unset() a variable passed by reference in a function, only the local variable will be destroyed, and the variables in the calling environment will maintain the same value before calling unset().
Example
<?php function foo(&$bar) { unset($bar); $bar = "blah"; } $bar = 'something'; echo "$bar\n"; foo($bar); echo "$bar\n"; ?>
The above routine will output:
something something
If you unset() a static variable in the function, then the static variable will be destroyed inside the function. However, when this function is called again, this static variable will be restored to the value it had before it was last destroyed.
Example
<?php function foo() { static $bar; $bar++; echo "Before unset: $bar, "; unset($bar); $bar = 23; echo "after unset: $bar\n"; } foo(); foo(); foo(); ?>
The above routine will output:
Before unset: 1, after unset: 23 Before unset: 2, after unset: 23 Before unset: 3, after unset: 23
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