Several common time interval information acquisition methods in PHP

Sometimes when we develop projects, we will encounter the start and end times of a few days ago, a few days later, today, this week, etc., get the previous months, get the number of days in this year, etc., the following is what I Summarized several common time-related methods, I hope they are useful to everyone:

1. Get the previous months

public function toSelfMonth($ m){
$today = input('param.today') ? input('param.today') : date("Y-m-d");
$arr = array();
$old_time = strtotime('-'.$m.' month',strtotime($today));
for($i = 0;$i <= $m; $i){
$t = strtotime( " $i month",$old_time);
$arr[]=date('Y-m',$t);
}
return $arr;
}

2. Get the date of the previous few days

public function toSelfDay($m){
$today = input('param .today') ? input('param.today') : date("Y-m-d");
$arr = array();
$old_time = strtotime('-'.$m.' day', strtotime($today));
for($i = 0;$i <= $m; $i){
$t = strtotime(" $i day",$old_time);
$arr[]=date('Y-m-d',$t);
}
return $arr;
}

## 3. Calculate the number of days in the previous months

public function getLastMonthDays($month){

$arr = $this->toSelfMonth($month);
$y = date ('Y',time());
$days = date('d',time());
for ($i=0;$i $days = $days date('t', strtotime($arr[$i]."-01"));
}
return $days;
}

4. Get the number of days in a certain monthpublic function getSelfMonthDays(){
/*$days = cal_days_in_month(CAL_GREGORIAN, 4, 2011);*/
$days = date( 't', strtotime("2011-4-1"));
/*$days = date("t");
echo "The number of days in the current month".$days."
";*/
return $days;
}

5. Get the start and end timestamps of the specified year and month

public function getSelfMonthStartEnd($y=0,$m=0){

$y = $y ? $y : date('Y');
$m = $m ? $m : date('m ');
$d = date('t', strtotime($y.'-'.$m));
return array("start"=>strtotime($y.'-'. $m),"end"=>mktime(23,59,59,$m,$d,$y));
}

6. Get the date interval

To get the time interval, you must first convert the time into a timestamp. Timestamps are generally measured in seconds, so the following measurement units are obtained:

(1) One hour is 3600s

(2) One day is 24*3600s, that is, 86400 seconds

According to these two conditions, the following method is obtained

function GetDateLong ($time1,$time2){

if($time2 >= $time1){

$long = $time2 - $time1;
}else{
$long = - ($time2 - $time1);
}
if($long > 0){
$year_day = $this->GetYearDay($time1);
$year = floor($ long/($year_day*86400));
$day = floor(($long)%($year_day*86400)/86400);
if($year >= 1){
return $ Year. 'Nian'. $ day. 'Heaven';
} else {
Return $ Day.
}


}


7. Get whether it is a leap year

If there are 365 days in a year, yes In ordinary years, when there are 366 days in a year, it is a leap year.
1. Ordinary leap year: The Gregorian calendar year is a multiple of 4, usually a leap year. (For example, 2004 is a leap year); 2. Century leap year: The Gregorian calendar year is a hundred, and it must be a multiple of 400 to be a leap year (for example, 1900 is not a century leap year, but 2000 is a century leap year).

According to this condition, we can get the following method to get whether it is a normal year or a leap year

public function GetYearType($year){

if ($year%4==0&&($year 0!=0 || $year@0==0)){

return 1;

}else{

return 2;
}
}




8. Determine how many days there are in a year

Same as the introduction of 7 above. The Gregorian calendar year is a multiple of 4, usually a leap year. Years in the Gregorian calendar are counted in hundreds and must be a multiple of 400 to be a leap year.

According to this condition, we can complete the method to get the number of days in a year

public function GetYearDay($time){
$year = date("Y",$time);
$a1 = $year/100;
if($a1 == 0){
$b1 = $year/400;
if($b1 > 0){
$ long = 365;
      }else{
                $long = 366;
                                                                                                                                                   . {
$long = 366;

#

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